10th Maths Chapter 1 Relations and Functions

10th Maths Chapter 1 Relations and Functions solutions, with the chapter's formulas and every exercise worked step by step, as per the 2026-27 Samacheer Kalvi textbook.

This chapter looks at ordered pairs, the Cartesian product of sets, and how a relation links one set to another. It then explains when a relation becomes a function, the ways a function can be shown, and the common types such as one-one, onto, many-one and into. In the exercises students form products, test relations, find domains and ranges, identify function types, and work out compositions of functions.

Exercises in this chapter

Key formulas

  • Cartesian product of A with B

    A×B={(a,b)∣for all a∈A, b∈B}A \times B = \{(a,b) \mid \text{for all } a \in A,\ b \in B\}

  • A relation R from A to B is a subset of A × B

    R⊆A×BR \subseteq A \times B

  • Condition for a relation R from X to Y to be a function

    for every x∈X there exists only one y∈Y\text{for every } x \in X \text{ there exists only one } y \in Y

  • Identity function

    f(x)=xf(x) = x

  • Reciprocal function

    f(x)=1xf(x) = \dfrac{1}{x}

  • Constant function

    f(x)=cf(x) = c

  • Linear function

    f(x)=ax+b, a≠0f(x) = ax + b,\ a \neq 0

  • Quadratic function

    f(x)=ax2+bx+c, a≠0f(x) = ax^{2} + bx + c,\ a \neq 0

  • Cubic function

    f(x)=ax3+bx2+cx+d, a≠0f(x) = ax^{3} + bx^{2} + cx + d,\ a \neq 0

  • Composition of two functions f : A → B and g : B → C

    g∘f:A→C,(g∘f)(x)=g(f(x))  for all x∈Ag \circ f : A \to C,\quad (g \circ f)(x) = g(f(x)) \ \text{ for all } x \in A

  • Composition is not commutative in general

    f∘g≠g∘ff \circ g \neq g \circ f

  • Composition is associative

    f∘(g∘h)=(f∘g)∘hf \circ (g \circ h) = (f \circ g) \circ h

Chapter 1 one-mark practice

  1. If n(A×B)=6n(A \times B) = 6 and A={1,3}A = \{1,3\} then n(B)n(B) is

    1. (1) 1
    2. (2) 2
    3. (3) 3
    4. (4) 6
    Show answer

    Answer: (3) 3

    1. n(A×B)=n(A)×n(B)n(A\times B)=n(A)\times n(B).

    2. 6=2×n(B)6=2\times n(B).

    3. n(B)=3n(B)=3.

    Question 1 of 10
  2. A={a,b,p}A = \{a,b,p\}, B={2,3}B = \{2,3\}, C={p,q,r,s}C = \{p,q,r,s\} then n[(A∪C)×B]n[(A \cup C) \times B] is

    1. (1) 8
    2. (2) 20
    3. (3) 12
    4. (4) 16
    Show answer

    Answer: (3) 12

    1. A∪C={a,b,p,q,r,s}A\cup C=\{a,b,p,q,r,s\}, so n(A∪C)=6n(A\cup C)=6.

    2. n(B)=2n(B)=2.

    3. n[(A∪C)×B]=6×2=12n[(A\cup C)\times B]=6\times 2=12.

    Question 2 of 10
  3. If A={1,2}A = \{1,2\}, B={1,2,3,4}B = \{1,2,3,4\}, C={5,6}C = \{5,6\} and D={5,6,7,8}D = \{5, 6, 7, 8\} then state which of the following statement is true.

    1. (1) (A×C)⊂(B×D)(A \times C) \subset (B \times D)
    2. (2) (B×D)⊂(A×C)(B \times D) \subset (A \times C)
    3. (3) (A×B)⊂(A×D)(A \times B) \subset (A \times D)
    4. (4) (D×A)⊂(B×A)(D \times A) \subset (B \times A)
    Show answer

    Answer: (1) (A×C)⊂(B×D)(A \times C) \subset (B \times D)

    1. A={1,2}⊂B={1,2,3,4}A=\{1,2\}\subset B=\{1,2,3,4\} and C={5,6}⊂D={5,6,7,8}C=\{5,6\}\subset D=\{5,6,7,8\}.

    2. So every pair of A×CA\times C is also a pair of B×DB\times D.

    3. Hence (A×C)⊂(B×D)(A\times C)\subset (B\times D).

    Question 3 of 10
  4. If there are 1024 relations from a set A={1,2,3,4,5}A = \{1, 2, 3, 4, 5\} to a set BB, then the number of elements in BB is

    1. (1) 3
    2. (2) 2
    3. (3) 4
    4. (4) 8
    Show answer

    Answer: (2) 2

    1. Number of relations from AA to BB is 2n(A)⋅n(B)2^{n(A)\cdot n(B)}.

    2. 25 n(B)=1024=2102^{5\,n(B)}=1024=2^{10}.

    3. 5 n(B)=10⇒n(B)=25\,n(B)=10\Rightarrow n(B)=2.

    Question 4 of 10
  5. The range of the relation R={(x,x2)∣xR = \{(x, x^2) \mid x is a prime number less than 13}\} is

    1. (1) {2,3,5,7}\{2,3,5,7\}
    2. (2) {2,3,5,7,11}\{2,3,5,7,11\}
    3. (3) {4,9,25,49,121}\{4,9,25,49,121\}
    4. (4) {1,4,9,25,49,121}\{1,4,9,25,49,121\}
    Show answer

    Answer: (3) {4,9,25,49,121}\{4,9,25,49,121\}

    1. Primes less than 13 are 2,3,5,7,112,3,5,7,11.

    2. Range consists of the squares x2x^{2}.

    3. Range ={4,9,25,49,121}=\{4,9,25,49,121\}.

    Question 5 of 10
  6. If the ordered pairs (a+2,4)(a + 2, 4) and (5,2a+b)(5, 2a + b) are equal then (a,b)(a,b) is

    1. (1) (2,−2)(2, -2)
    2. (2) (5,1)(5,1)
    3. (3) (2,3)(2,3)
    4. (4) (3,−2)(3, -2)
    Show answer

    Answer: (4) (3,−2)(3, -2)

    1. Equal ordered pairs: a+2=5a+2=5 and 2a+b=42a+b=4.

    2. a=3a=3.

    3. 2(3)+b=4⇒b=−22(3)+b=4\Rightarrow b=-2.

    Question 6 of 10
  7. Let n(A)=mn(A) = m and n(B)=nn(B) = n then the total number of non-empty relations that can be defined from AA to BB is

    1. (1) mnm^n
    2. (2) nmn^m
    3. (3) 2mn−12^{mn} - 1
    4. (4) 2mn2^{mn}
    Show answer

    Answer: (3) 2mn−12^{mn} - 1

    1. Total number of relations from AA to BB is 2mn2^{mn}.

    2. Remove the empty relation.

    3. Non-empty relations =2mn−1=2^{mn}-1.

    Question 7 of 10
  8. If {(a,8),(6,b)}\{(a,8),(6,b)\} represents an identity function, then the value of aa and bb are respectively

    1. (1) (8,6)(8,6)
    2. (2) (8,8)(8,8)
    3. (3) (6,8)(6,8)
    4. (4) (6,6)(6,6)
    Show answer

    Answer: (1) (8,6)(8,6)

    1. For an identity function f(x)=xf(x)=x, each pair is of the form (x,x)(x,x).

    2. (a,8)⇒a=8(a,8)\Rightarrow a=8.

    3. (6,b)⇒b=6(6,b)\Rightarrow b=6.

    Question 8 of 10
  9. Let A={1,2,3,4}A = \{1,2,3,4\} and B={4,8,9,10}B = \{4,8,9,10\}. A function f:A→Bf : A \to B given by f={(1,4),(2,8),(3,9),(4,10)}f = \{(1,4),(2,8),(3,9),(4,10)\} is a

    1. (1) Many-one function
    2. (2) Identity function
    3. (3) One-to-one function
    4. (4) Into function
    Show answer

    Answer: (3) One-to-one function

    1. Images are 4,8,9,104,8,9,10 — all different.

    2. Different elements of AA have different images.

    3. So ff is one-to-one.

    Question 9 of 10
  10. If f(x)=2x2f(x) = 2x^2 and g(x)=13xg(x) = \dfrac{1}{3x}, then f∘gf \circ g is

    1. (1) 32x2\dfrac{3}{2x^2}
    2. (2) 23x2\dfrac{2}{3x^2}
    3. (3) 29x2\dfrac{2}{9x^2}
    4. (4) 16x2\dfrac{1}{6x^2}
    Show answer

    Answer: (3) 29x2\dfrac{2}{9x^2}

    1. (f∘g)(x)=f(g(x))=f(13x)(f\circ g)(x)=f\big(g(x)\big)=f\left(\dfrac{1}{3x}\right).

    2. =2(13x)2=2\left(\dfrac{1}{3x}\right)^{2}.

    3. =29x2=\dfrac{2}{9x^{2}}.

    Question 10 of 10

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